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📅 May 14, 2026 👤 scraface

May 14, 2026

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We want the largest such \( v \).
First, solve the inequality:
v^2 < 600 \Rightarrow v < \sqrt{600}
Approximate \( \sqrt{600} \):
\sqrt{600} = \sqrt{100 \times 6} = 10\sqrt{6} \approx 10 \times 2.449...
So, \( v < 24.49 \). Since \( v \) is a multiple of 5, the possible va...
Check \( v = 25 \): \( 25^2 = 625 > 600 \) → too large.
Check \( v = 20 \): \( 20^2 = 400 < 600 \) → valid.
Thus, the greatest possible value of \( v \) is \(\boxed{20}\).
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